rvanveshana.com
t = 0.00s
λ = 25.0 px

Live Telemetry & Summary

Observe the matter wave. As you increase the particle's mass or velocity, its momentum increases. Consequently, the de Broglie wavelength compresses, making the pilot wave pack tightly.

Particle Mass (m):2.0 kg
Particle Velocity (v):4.0 m/s
Momentum (p = mv):8.00 kg·m/s
De Broglie Wavelength (λ):25.00 px

Variable Adjuster

Particle Mass (m)2kg
15
Particle Velocity (v)4m/s
110

De Broglie Wavelength

DBRG

De Broglie's hypothesis states that all matter exhibits wave-like properties. A moving particle of mass m and velocity v has a de Broglie wavelength λ inversely proportional to its momentum p. This pilot wave represents the probability amplitude of finding the particle at a given point in space.

λ=hp=hmv\lambda = \frac{h}{p} = \frac{h}{mv}

Whiteboard Solver Steps

Step 1

Classical Momentum (p)

The linear momentum of the particle is the product of its mass and velocity.

p=m⋅v=2.0⋅4.0=8.00p = m \cdot v = 2.0 \cdot 4.0 = 8.00
Step 2

De Broglie Wavelength (λ)

Any moving matter has an associated probability wave whose wavelength is inversely proportional to its momentum.

λ=hp=2008.00=25.00 pixels\lambda = \frac{h}{p} = \frac{200}{8.00} = 25.00\text{ pixels}