rvanveshana.com
t = 0.00s
10kg
State: STATIC (LOCKED) • Net Force: 0.0 N • Accel: 0.00 m/s²

Live Telemetry & Summary

Observe the live values changing in real-time as the simulation runs. Tweak parameters and press **Simulate** to see new calculations.

Time:0.00 s
Acceleration:0.00 m/s²
Instant Speed:0.0 m/s
Displacement:0.0 m
Net Force (F_net):0.0 N

Variable Adjuster

Applied Force (F)40N
-100100
Crate Mass (m)10kg
250
Static Friction (μ_s)0.5
01
Kinetic Friction (μ_k)0.3
01
Slope Angle (θ)15°
045

Newtonian Forces Lab

FORC

Newton's Second Law states that force equals mass times acceleration (F = ma). Here, we model applied horizontal forces acting on a mass against surface static and kinetic friction forces.

Fnet=Fapplied−Ffriction=maF_{net} = F_{applied} - F_{friction} = ma

Whiteboard Solver Steps

Step 1

Normal Force & Component Decomposition

Gravity is split into two components: perpendicular (mgcos⁡θmg\cos\theta, countered by Normal force) and parallel (mgsin⁡θmg\sin\theta, pulling it down the slope).

FN=mgcos⁡(θ)=94.7 N,Fg,∥=mgsin⁡(θ)=25.4 NF_N = mg \cos(\theta) = 94.7 \text{ N}, \quad F_{g,\parallel} = mg \sin(\theta) = 25.4 \text{ N}
Step 2

Threshold Analysis & Friction Calculation

The driving force (Applied Force minus Gravity Parallel) does not overcome static friction. The crate remains stationary.

∣Fdrive∣=14.6 N≤Fs,max⇒Ffriction=−Fdrive=−14.6 N|F_{drive}| = 14.6 \text{ N} \le F_{s,max} \Rightarrow F_{friction} = -F_{drive} = -14.6 \text{ N}
Step 3

Acceleration Output

By Newton's Second Law, the net force acting on the mass produces an acceleration in the direction of the net force.

a=Fnetm=0.0010=0.00 m/s2a = \frac{F_{net}}{m} = \frac{0.00}{10} = 0.00 \text{ m/s}^2