t = 0.00s
Deflection Force (F)

Live Telemetry & Summary

Observe how charge polarity flips deflection direction, and how B-field strength curves the orbit.

Force Magnitude (F):3.000e-4 N
Orbital Radius (r):0.011 m

Variable Adjuster

Charge (q)5ฮผC
-1010
Velocity (v)40m/s
1080
Magnetic Field (B)1.5T
0.53

Lorentz Force Deflection

LORE

The Lorentz Force describes the combination of electric and magnetic forces on a point charge. In a uniform magnetic field, a moving charge experiences a magnetic force perpendicular to both its velocity and the magnetic field vectors. This centripetal force deflects the charge into a circular orbit (cyclotron path).

F=q(vร—B)โ‡’r=mvโˆฃqโˆฃB\mathbf{F} = q(\mathbf{v} \times \mathbf{B}) \Rightarrow r = \frac{mv}{|q|B}

Whiteboard Solver Steps

Step 1

Lorentz Magnetic Force Equation

A moving electric charge inside a magnetic field experiences a perpendicular force. The direction is determined by the Right-Hand Rule.

F=q(vร—B)โ‡’F=โˆฃqโˆฃvB\mathbf{F} = q (\mathbf{v} \times \mathbf{B}) \Rightarrow F = |q| v B
Step 2

Force Magnitude Calculation

This side deflection force acts perpendicularly to both velocity and magnetic field vectors at all times.

F=โˆฃ5โ‹…10โˆ’6โˆฃโ‹…40โ‹…1.5=3.000eโˆ’4 NF = |5 \cdot 10^{-6}| \cdot 40 \cdot 1.5 = 3.000e-4 \text{ N}
Step 3

Cyclotron Orbital Radius

Since the force is always perpendicular to velocity, it acts as a centripetal force, keeping the charge in a uniform circular orbit.

r=mvโˆฃqโˆฃB=(2โ‹…10โˆ’9)โ‹…40โˆฃ5โ‹…10โˆ’6โˆฃโ‹…1.5=0.011 mr = \frac{mv}{|q|B} = \frac{(2 \cdot 10^{-9}) \cdot 40}{|5 \cdot 10^{-6}| \cdot 1.5} = 0.011 \text{ m}